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假设有个电话是001-0001你的程序会输出些什么?

Posted by frkstyc at 2005-03-24 09:30:37 on Problem 1002
In Reply To:WA,跪求高人指点 Posted by:850910 at 2005-03-24 08:55:53
> #include<iostream.h>
> 
> int main()
> {
> 	int a[100010],b[100010]={0};
> 	char x[1000];
> 	int t,num,cn=0,an;
> 	cin>>t;
> 	for(int i=0;i<t;i++)
> 	{
> 		num=0;
> 		an=0;
> 		cin>>x;
> 		int count=0;
> 		for(int j=0;;j++)
> 		{
> 			
> 			if(x[j]>='0'&&x[j]<='9') { num=num*10+int(x[j]-'0'); count++; }
> 			if(x[j]=='A'||x[j]=='B'||x[j]=='C') {num=num*10+2; count++; }
> 			if(x[j]=='D'||x[j]=='E'||x[j]=='F') {num=num*10+3; count++; }
> 			if(x[j]=='G'||x[j]=='H'||x[j]=='I') {num=num*10+4; count++; }
> 			if(x[j]=='J'||x[j]=='K'||x[j]=='L') {num=num*10+5; count++; }
> 			if(x[j]=='M'||x[j]=='N'||x[j]=='O') {num=num*10+6; count++; }
> 			if(x[j]=='P'||x[j]=='R'||x[j]=='S') {num=num*10+7; count++; }
> 			if(x[j]=='T'||x[j]=='U'||x[j]=='V') {num=num*10+8; count++; }
> 			if(x[j]=='W'||x[j]=='X'||x[j]=='Y') {num=num*10+9; count++; }
> 			//cout<<x[j]<<' '<<num<<endl;
> 			if(count==7) break;
> 		}
> 		//cout<<num<<endl;
> 		for(int k=0;k<cn;k++)
> 		{
> 			if(num==a[k])
> 			{
> 				b[k]++;
> 				an=1;
> 				break;
> 			}
> 		}
> 		if(an==0) 
> 		{
> 			a[cn]=num;
> 			//cout<<a[cn]<<endl;
> 			b[cn]++;
> 			//cout<<b[cn]<<endl;
> 			//cout<<cn<<endl;
> 			cn++;
> 		}
> 	}
> 	for(int pass=1;pass<cn;pass++)
> 	{
> 		int temp1,temp2;
> 		for(int i=0;i<cn-pass;i++)
> 		{
> 			if(a[i]>a[i+1])
> 			{
> 				temp1=a[i];
> 				temp2=b[i];
> 				a[i]=a[i+1];
> 				b[i]=b[i+1];
> 				a[i+1]=temp1;
> 				b[i+1]=temp2;
> 			}
> 		}
> 	}
> 
> 	//cout<<b[0]<<' '<<b[1]<<' '<<b[2]<<endl;
> 	int number=0;
> 	for(int q=0;q<cn;q++)
> 	{
> 		if(b[q]>1)
> 		{
> 			//cout<<a[q]<<' ';
> 			cout<<a[q]/10000<<'-'<<a[q]%10000<<' '<<b[q]<<endl;
> 			number++;
> 		}
> 	}
> 	if(number==0) cout<<"No duplicates."<<endl;
> 
> 	return 0;
> }
> 
> 
> 
> 
> 
> 
> 
> 

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