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O(n*a*t)----->O(a*t)

Posted by library2 at 2009-10-25 04:55:07 on Problem 3046 and last updated at 2009-10-25 04:59:24 
把O(n*t^20）方法中f[j]与f[j+1] 的方程列出来后做差，O（n*t）方程便出炉。
注意：由于过程中mod10^6 所以算出的数可能为负数，用10^6加上即可
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