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左边第i个点出来的边为2^(n - i)，也许可以？另：其实这题可以参考1904In Reply To:Re:左边第1个点连去右边的权都是10e10的倍数，第2个点连去右边的权都是10e9的倍数，类推。估计就行了 Posted by:20071002871 at 2009-10-24 21:23:04 > 若点数变大，权值按类似方法就容不下了吧。。。 Followed by: Post your reply here: |
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