> #include<iostream.h>
> #include<math.h>
> void main()
> {
> 	int n,k,q,r,e;
> 	char ch1[2],ch2[2];
> 	cin>>n;
> 	for(int i=1;i<=n;i++)
> 	{
> 		cin>>ch1>>ch2;
> 	
>                 //王 等于差的绝对值中较大的一个
> 		k=(abs(ch1[0]-ch2[0])>abs(ch1[1]-ch2[1])?abs(ch1[0]-ch2[0]):abs(ch1[1]-ch2[1]));
>                 //后 等于1或2
> 		if((ch1[0]==ch2[0])||(ch1[1]==ch2[1])||(abs(ch1[0]-ch2[0])==abs(ch1[1]-ch2[1])))
> 			q=1;
> 		else
> 			q=2;
>                  //车 等于1或2
> 		if((ch1[0]==ch2[0])||ch1[1]==ch2[1])
> 			r=1;
> 		else
> 			r=2;
>                 //象 处于正方形对角线上时为1
> 		if(abs(ch1[0]-ch2[0])==abs(ch1[1]-ch2[1]))
> 			e=1;
> 		else
> 		{
> 	                int m=abs(ch1[0]-ch2[0])+abs(ch1[1]-ch2[1]);
>                         差的绝对值之和为偶数时等于2，为奇数时不能到达
> 			if(m%2==0)
> 				e=2;
> 			else
> 				e=0;
> 		}
>                  //输出结果
> 		if(e)
> 			cout<<k<<" "<<q<<" "<<r<<" "<<e<<endl;
> 		else
> 			cout<<k<<" "<<q<<" "<<r<<" "<<"Inf"<<endl;
> 	}
> }