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Re:按照《背包9讲》的伪代码,多重背包,1次AC,注意f[i]初始化为0~In Reply To:按照《背包9讲》的伪代码,多重背包,1次AC,注意f[i]初始化为0~ Posted by:erikajason at 2009-08-18 17:30:43 > 比较特别的是这题的cost和weight是一回事。所以函数的形参还可以少一个。 用背包9讲中的伪代码为什么老是Rumtime Error #include<stdio.h> #include<string.h> const int maxN = 11; const long maxcash = 100001; long cash; long f[maxcash+1]; void zeroOnePack( long cost, long weight ) { long i; for ( i=cash; i>=cost; i-- ) { if(f[i]<f[i-cost]+weight) f[i] = f[i-cost] + weight; } } void completPack( long cost, long weight ) { long i; for( i=cost; i<=cash; i++ ) { if( f[i]<f[i-cost] + weight ) f[i] = f[i-cost] + weight; } } void multiplePack ( long cost, long weight, long account) { int k; if( account*weight>=cash ) { completPack ( cost, weight); } else { k = 1; while ( k<account ) { zeroOnePack (k*cost, k*weight); k = k*2; account -= k; } zeroOnePack (account*cost,account*weight); } } int main() { long N, n[maxN], D[maxN], i; freopen( "input.in", "r", stdin); while( scanf("%ld%ld", &cash, &N)==2 ) { for ( i=1; i<=N; i++) { scanf("%ld%ld", &n[i], &D[i]); } memset(f, 0, sizeof(f)); for ( i=1; i<=N; i++ ) { multiplePack (D[i],D[i],n[i]); } printf("%ld\n",f[cash]); } return 0; } Followed by:
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