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Re:1个dfs就过了...

Posted by Justlikeanddoit at 2009-10-01 20:18:34 on Problem 2157
In Reply To:3个dfs也0ms过了 Posted by:onlyzeus at 2009-08-27 23:26:39
> 第一步:每次拿钥匙并检查能否开门;这一步拿过的钥匙要改为‘.’,开过的门也要改为‘.’
> 第二步:重复第一步的过程;
> 第三步:最后一次dfs,如果在整个图中能找到G就ok了
> 具体想法其实想下也不难,第一二步是为了能够打开从S出发能够打开的所有门;至于为什么要两步呢?第一步肯定会遍历能够遍历的点 但第一次遇见门时不一定拿到了该拿到的钥匙;于是在遍历一次该开的门开;
> 

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