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a[1]=1;a[2]=1;a[n]=a[n-1]+a[n-2];

Posted by TN at 2005-03-16 20:14:24 on Problem 1953
In Reply To:Re:谁能说说算法呀!! Posted by:zjpgalois at 2005-03-16 16:22:12
> 斐波那切数列

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