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Re:谁能说说算法呀!!

Posted by zjpgalois at 2005-03-16 16:22:12 on Problem 1953
In Reply To:谁能说说算法呀!! Posted by:00430030 at 2005-01-29 16:19:28

斐波那切数列

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a[1]=1;a[2]=1;a[n]=a[n-1]+a[n-2]; (10) TN 2005-03-16 20:14:24
- 不对吧？a1＝2，a2＝3，然后才是递推。。好像还要int64。。 (0) yangguo981 2006-05-20 10:34:30
  - Re:不对吧？a1＝2，a2＝3，然后才是递推。。好像还要int64。。 (14) KosonLau 2007-04-22 13:47:39
- Re:a[1]=1;a[2]=1;a[n]=a[n-1]+a[n-2]; (2) fengzunbao2006 2007-12-13 00:19:17

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