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枚举也能1AC！

Posted by xiao_si at 2009-09-12 01:57:42 on Problem 2965 and last updated at 2009-09-12 02:05:15 
首先应该明白两点：
1 不论翻转执行的先后序列如何，结果都一样。
2 每一个点（i,j）最多做一次翻转。（由1不难得到）
所以结果可以转化为一个只包含0、1的十六位字符串，枚举所有的字符串逐个检验，取包含1最少的串（若果1代表翻转的话）。

枚举 一种实现为 for(int i=1;i<(1<<16);++i)Test(i)
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