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a b都是设为整形,但你所列的表达式的结果不一定是整形In Reply To:Re:为什么还是错的?help me !!附程序 Posted by:cancel at 2005-10-05 22:39:25 > #include<iostream.h>
>
> void caculate(int f0,int f1,int f2)
> {
> int a,b,c,f3,f4,f5;
> c=f0;
> a=(f0-2*f1+f2)/2;
> b=(-3*f0+4*f1-f2)/2;
> f3=9*a+3*b+c;
> f4=16*a+4*b+c;
> f5=25*a+5*b+c;
> cout<<f3<<" "<<f4<<" "<<f5<<endl;
> }
>
>
>
> int main()
> {
> int f0,f1,f2,n;
> n=0;
> while(n<100)
> {
> cin>>f0>>f1>>f2;
> caculate(f0,f1,f2);
> n++;
> }
>
> return 0;
>
> }
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