对换矩阵
2 1 1 0
1 2 0 1
1 0 2 1
0 1 1 2
B=PT A P

Rn=A Rn-1=A^n R0=(P B PT)^n R0=P B^n PT R0
得到【4^(n-1)+2^(n-1)     4^(n-1)     4^(n-1)    4^(n-1)-2^(n-1)】
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