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把h代到r里面,可以得到r=sqrt(s/pi/4)

Posted by scrooke at 2009-09-05 16:00:58 on Problem 3737
In Reply To:弱弱的公式推导- -。。大牛就别进来了看笑话了~~ Posted by:conanhjj at 2009-05-21 00:58:58
> S=pi*r*l + pi*r*r
> l=sqrt(r*r+h*h), 联立得, r*2= s*s/(pi*pi*h*h+2*pi*s)
> V=(1/3)*pi*r*r*h,代入r*2,求导,令一阶导数为0,得出结果
> 
> h=sqrt(2*s/pi)
> r=sqrt(s*s/(pi*pi*h*h+2*pi*s))
> v=(1.0/3.0)*(s*s)*h/(pi*h*h+2*s)
> 
> 方便一下数学苦手的人。。
> 
> 

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