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Re:the Chinese remainder theoremIn Reply To:请问大家怎样才能不超时?痛苦死了 Posted by:yeti at 2005-03-12 03:00:45 > #include<iostream.h>
> #include<math.h>
> void main()
> {
>
> int p,e,i,d,t=0,u=0;
> while(1){
> u++;
> cin>>p>>e>>i>>d;
> if(p==-1 && e==-1 && i==-1 && d==-1) break;
> for(t=d+1;;t++){
> if((t-p)%23==0 && (t-e)%28==0 && (t-i)%33==0){
> cout<<"Case "<<u
> <<": the next triple peak occurs in "
> <<t-d<<" days."<<endl;
> break;
> }
> }
>
> }
> }
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