#include<iostream.h>
#include<math.h>
void main()
{
	
	int p,e,i,d,t=0,u=0;
	while(1){
		u++;
		cin>>p>>e>>i>>d;
		if(p==-1 && e==-1 && i==-1 && d==-1) break;
		for(t=d+1;;t++){
			if((t-p)%23==0 && (t-e)%28==0 && (t-i)%33==0){
					cout<<"Case "<<u
					<<": the next triple peak occurs in "
					<<t-d<<" days."<<endl;
					break;
				}
		}
		
	}
}

• Re:the Chinese remainder theorem (414) yesiam 2005-03-12 09:06:41