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水题~~~ 一次 AC~#include<iostream> #include<string.h> using namespace std; int a[20],b[20];char sa[20],sb[20]; int i,j,len,t,x,y,sum; int fun(int p) { int w=1; while(p) {w*=10; p--; } return w; } int convert(char *s) { int res=0; memset(a,0,sizeof(a)); len=strlen(s); for(i=0;i<len;i++) a[i]=(s[i]-'0'); for(i=0;i<len;i++) res+=a[i]*fun(i); return res; } int reverse(int z) { int ans=0; memset(b,0,sizeof(b)); for(i=0;i<20;i++) b[i]=z%fun(i+1)/fun(i); for(i=19;;i--) if(b[i]!=0) break; for(j=i;j>=0;j--) ans+=b[j]*fun(i-j); return ans; } int main() { scanf("%d",&t); while(t--) { scanf("%s%s",&sa,&sb); x=convert(sa); y=convert(sb); sum=x+y; printf("%d\n",reverse(sum)); } system("pause"); return 0; } Followed by: Post your reply here: |
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