佩服,
if(int==double)
你也敢用...

> #include<iostream>
> #include<math.h>
> using namespace std;
> int fun(int n)
> {
> 	double k;
> 	k=sqrt(double(2)*n+0.25)-0.5;
> 	if(k==int(k))
> 		return int(k)-1;
> 	else
> 		return int(k);
> }
> int main()
> {
> 	int k,m,n;
> 	while(cin>>n)
> 	{
> 		k=fun(n);
> 		m=n-k*(k+1)/2;
> 		if(k%2)
> 			cout<<"TERM "<<n<<" IS "<<m<<'/'<<k+2-m<<endl;
> 		else
> 			cout<<"TERM "<<n<<" IS "<<k+2-m<<'/'<<m<<endl;
> 	}
> 	return 0;
> }