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无聊的题目 ……就是一个公式嘛#include <iostream>
using namespace std;
int main()
{
__int64 n,m;
while(scanf("%I64d%I64d",&n,&m)!=EOF)
{
if((m*n)%(m-1)==0)
{
printf("%I64d\n",(m*n)/(m-1)-1);
}
else
{
printf("%I64d\n",(m*n)/(m-1));
}
}
return 0;
}
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