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无聊的题目 ……就是一个公式嘛#include <iostream> using namespace std; int main() { __int64 n,m; while(scanf("%I64d%I64d",&n,&m)!=EOF) { if((m*n)%(m-1)==0) { printf("%I64d\n",(m*n)/(m-1)-1); } else { printf("%I64d\n",(m*n)/(m-1)); } } return 0; } Followed by: Post your reply here: |
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