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无聊的题目 ……就是一个公式嘛

Posted by leon_L at 2009-08-25 16:45:27 on Problem 2509
#include <iostream>
using namespace std;

int main()
{
    __int64 n,m;
    
    while(scanf("%I64d%I64d",&n,&m)!=EOF)
    {
                                   if((m*n)%(m-1)==0)
                                   {
                                                     printf("%I64d\n",(m*n)/(m-1)-1);
                                   }
                                   else
                                   {
                                       printf("%I64d\n",(m*n)/(m-1));
                                   }
                                                     
    }
    
    return 0;
}

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