Online JudgeProblem SetAuthorsOnline ContestsUser
Web Board
Home Page
F.A.Qs
Statistical Charts
Problems
Submit Problem
Online Status
Prob.ID:
Register
Update your info
Authors ranklist
 Current Contest
Past Contests
Scheduled Contests
Award Contest
User ID:
Password:
  Register

the same...

Posted by Zeor at 2009-08-23 12:58:49 on Problem 3741 and last updated at 2009-08-23 12:58:57
In Reply To:Re:why 3*2^2 + 2*2^1 + 1*2^0 = 15? Posted by:AekdyCoin at 2009-08-23 12:46:04 
> 321->(base 2 system.b2)3*2^2+2*2^1+1*2^0=17->(Q system.Q=4)->101(that is 1*4^2 + 0*4^1+ 1*4^0 )->(P sys.p=2)->5(1*2^2+0*2^1+1*2^0)->(Q sys.q=4)->11->(P sys)->3->(Q sys)->3->(P sys)->3...
> 
> i think it must be 17.
Followed by:
Post your reply here:
User ID:
Password:
Title:

Content:

Home Page   Go Back  To top

All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator