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Re:why 3*2^2 + 2*2^1 + 1*2^0 = 15?

Posted by AekdyCoin at 2009-08-23 12:46:04 on Problem 3741
In Reply To:why 3*2^2 + 2*2^1 + 1*2^0 = 15? Posted by:deadopen at 2009-08-23 12:38:08
321->(base 2 system.b2)3*2^2+2*2^1+1*2^0=17->(Q system.Q=4)->101(that is 1*4^2 + 0*4^1+ 1*4^0 )->(P sys.p=2)->5(1*2^2+0*2^1+1*2^0)->(Q sys.q=4)->11->(P sys)->3->(Q sys)->3->(P sys)->3...

i think it must be 17.

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