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贪心,说下 思路~设个标记num 初始值 置为0; 从 n*m 开始向下查找,如果手中有那张牌,num++; 否则 num--; 记录num 出现过的 最大值~ 我看的一位大牛的解题报告~方法真牛逼啊~ Followed by: Post your reply here: |
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