| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
Re:我的代码是这样的,为什么。。。。In Reply To:我的代码是这样的,为什么。。。。 Posted by:LittleCarol at 2009-07-03 15:33:56 > #include <stdio.h>
> #include <math.h>
>
> int main()
> {
> float humidex, temperature, dewpoint;
> float h, e;
>
> char c1, c2;
> float tmp1, tmp2;
> while(scanf("%c", &c1), c1!='E')
> {
>
> scanf("%f %c %f", &tmp1, &c2, &tmp2);
> switch(c1+c2)
> {
> case 'T'+'D':
> temperature = (c1 == 'T')?tmp1:tmp2;
> dewpoint = (c1 == 'D')?tmp1:tmp2;
> e = (float)(6.11 * exp(5417.753 * ((1/273.16) - (1/(dewpoint + 273.16)))));
> h = (float)(0.5555 * (e - 10.0));
> humidex = temperature + h;
> break;
> case 'T'+'H':
> temperature = (c1 == 'T')?tmp1:tmp2;
> humidex = (c1 == 'H')?tmp1:tmp2;
> h = (humidex - temperature);
> e = (float)(h/0.5555 + 10.0);
> dewpoint = 1/((1/273.16) - (log(e/6.11))/5417.753) - 273.16;
> break;
> case 'H'+'D':
> humidex = (c1 == 'H')?tmp1:tmp2;
> dewpoint = (c1 == 'D')?tmp1:tmp2;
> e = (float)(6.11 * exp(5417.753 * ((1/273.16) - (1/(dewpoint + 273.16)))));
> h = (float)(0.5555 * (e - 10.0));
> temperature = humidex - h;
> break;
> default:
> break;
>
> }
> printf("T %.1f D %.1f H %.1f\n", temperature, dewpoint, humidex);
> scanf("%c", &c1);//为什么一定要加这一句呢?这里才c1得到的是一个回车符
>
> }
> return 0;
> }
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator