#include<iostream>
#include<math>
using namespace std;
int main()
{
	int b,n;
	int a;
	
	cin>>b>>n;
	while(b!=0 && n!=0)
	{
		for(a=1;a<=b;a++)
		{
			if(abs(b-pow(a,n))<=abs(b-pow(a+1,n)) && abs(b-pow(a,n))<=abs(b-pow(a-1,n)))
			{
				cout<<a<<endl;
				break;
			}
		}
		cin>>b>>n;
	}
	
	
	
	return 0;
}

• Re:可以成功运行的，为何不对呢？ (385) huxipeng 2012-09-30 20:06:53