> 输入 3
> 输出 3
> 输入 10. zac 0
> 输出 3 chuen 0
> 输入 0. pop 0
> 输出1 imix 0
> 输入 10. zac 1995
> 输出 9 cimi 2801
> 
> 
> 输入有两个空格 输出也有两个空格
> 描述得太不清楚了
> 
>  #include"iostream"
> #include"string"
> using namespace std;
> int main()
> {
> 	int n;
> 	cin>>n;
> 	cout<<n<<endl;
> 	char str[][7]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
>     char nt[][9]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
> 	int i;
> 	int dh=0,yh=0;
> 	int dt,yt,k;
> 	long int days=0;		
> 	char s[7];
> 	while(n--)
> 	{
> 		scanf("%d. %s %d",&dh,s,&yh);
> 		for(i=0;i<19;i++)
> 			if(!strcmp(str[i],s)) break;
> 		days=365*yh+i*20+dh;
> 		yt=days/260;
> 		days=days-yt*260;
> 	    dt=days%13+1;
> 		k=days%20;
> 		printf("%d %s %d\n",dt,nt[k],yt);
> 	}
> 	return 0;
> }