#include<iostream>
#include<math.h>
using namespace std;
int main()
{
	int k,m,n;
	while(cin>>n&&n)
	{
		k=sqrt(double(2)*n+0.25)-0.5;
		m=n-k*(k+1)/2;
		cout<<n<<' '<<m*(k+1)+k*(k+1)*(2*k+1)/6<<endl;
	}
	return 0;
}