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Re:暴力方法,一个一个排除,0MS过了,大牛见笑

Posted by kakassi at 2009-08-08 05:53:53 on Problem 1316
In Reply To:暴力方法,一个一个排除,0MS过了,大牛见笑 Posted by:bhq at 2009-07-31 15:16:30
我抄了 谢谢

> //如果某数有generator,它一定可以拆成:i*1001 + j*101 + k*11 + m*2   0<=i,j,k,m<=9
> //数组开到9*1001+9*101+9*11+9*2+1=10036
> 
> #include <iostream>
> using namespace std;
> 
> int main()
> {
> 	int selfnum[10036] = {0};
> 	for ( int i = 0 ; i < 10 ; ++ i )
> 		for ( int j = 0 ; j < 10 ; ++ j )
> 			for ( int k = 0 ; k < 10 ; ++ k )
> 				for ( int m = 0 ; m < 10 ; ++ m )
> 					selfnum[ i*1001 + j*101 + k*11 + m*2 ] = 1;
> 	for ( int i = 1 ; i <= 10000 ; ++ i  )
> 		if ( selfnum[i] == 0 )
> 			cout << i << endl;
> 	return 0;
> }

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