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1422Air Raid 帮忙分析一下 又是测试通过 提交WA#include<iostream>
using namespace std;
bool str[121][121];
int ans[1000];
int strnum,lnum;
void in()
{
cin>>strnum;
cin>>lnum;
int a,b;
for(int i=0;i<lnum;i++)
{
cin>>a>>b;
str[a][b]=1;
}
}
int bipartitl()//匈牙利算法,根据师兄的模板写的
{
int q[121],prev[121],t,r;//prev存储交错链和,同时表示右边的点是否用过
int vm1[121],vm2[121];//二部图的两边
int n=0;
int i,j,x;
for(i=1;i<=strnum;i++)
{
vm1[i]=-1;
vm2[i]=-1;
}
for(i=1;i<=strnum;i++)
{
if(vm1[i]!=-1) continue;
memset(q,0,sizeof(q));
t=r=0;
for(j=1;j<=strnum;j++) prev[i]=-2;
for(j=1;j<=strnum;j++)
{
if(str[i][j])
{
prev[j]=-1;
q[r++]=j;
}
}
while(t!=r)
{
x=q[t];
if(vm2[x]==-1) break;
t++;
for(j=1;j<=strnum;j++)
if(prev[j]==-2&&str[vm2[x]][j])
{
prev[j]=x;
q[r++]=j;
}
}
if(t==r) continue;
while(prev[x]>-1)
{
vm1[vm2[prev[x]]]=x;
vm2[x]=vm2[prev[x]];
x=prev[x];
}
vm1[i]=x;
vm2[x]=i;
n++;
}
return n;
}
int main()
{
int casnum;
cin>>casnum;
for(int cas=1;cas<=casnum;cas++)
{
memset(str,0,sizeof(str));
in();
ans[cas-1]=strnum-bipartitl();
}
for(int k=0;k<casnum;k++)
cout<<ans[k]<<endl;
return 0;
}
谢谢各位了
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