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Re:超时,大牛帮帮忙,简化一下啊

Posted by 10074182 at 2009-08-04 16:11:32 on Problem 2498
In Reply To:超时,大牛帮帮忙,简化一下啊 Posted by:10074182 at 2009-08-04 15:36:38
> #include <stdio.h>
> #include<stdlib.h>
> #include<string.h>
> int main()
> {
> 	int n,i,j,len,k,h,fac,need,sum;
> 	char id[8];
> 	scanf("%d",&n);	
> 	for(i=1;i<=n;i++)
> 	{
> 		scanf("%s",id);
> 		len=strlen(id);
> 		sum=0;
> 		for(j=len-1;j>=0;j--)
> 		{
> 			if(id[j]!='?')
> 			{
> 				if((len-j)%3==1)
> 					sum+=(id[j]-'0')*9;
> 				else if((len-j)%3==2)
> 					sum+=(id[j]-'0')*3;
> 				else
> 					sum+=(id[j]-'0')*7;
> 			}
> 			else
> 				k=j;
> 		}
> 		need=10-sum%10;        \\要加数的个位数字 
> 		printf("Scenario #%d:\n",i);
> 		if((len-k)%3==1)
> 			fac=9;
> 		else if((len-k)%3==2)
> 			fac=3;
> 		else 
> 	    	fac=7;
> 		for(h=1;h<=9;h++)
> 			if((h*fac)%10==need)
> 				break;
> 		id[k]=h+'0';
> 		printf("%s\n\n",id);	
> 	}
> 	system("pause");
> 	return 0;
> }

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