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纯枚举就能过啊,献上代码#include <iostream> using namespace std; int main () { int a,b,k,i; cin>>k; for (i=0;i<k;i++) { cin>>a>>b; if (a==b&&a%2==0) { cout<<a*2<<endl; continue; } if (a==b&&a%2==1) { cout<<(a-1)*2+1<<endl; continue; } if (a==(b+2)&&a%2==0) { cout<<(a-1)*2<<endl; continue; } if (a==(b+2)&&a%2==1) { cout<<(a-2)*2+1<<endl; continue; } if (a!=b+2&&a!=b) { cout<<"No Number"<<endl; continue; } } return 0; } Followed by: Post your reply here: |
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