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111#include <iostream> using namespace std; int main() { int n; double e=0,sum=1; cout<<"n e\n- -----------\n"; for(n=0;n<=9;n++) { if(n!=0) sum=n*sum; e+=1/sum; if(n<=2) cout<<n<<" "<<e<<endl; else printf("%d %.9lf\n",n,e); } system("pause"); return 0; } Followed by: Post your reply here: |
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