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虽然过了，但觉得有些不妥，自己又不知道哪不妥，路过的帮看看.我的做法是只要有一个根的子树有两种情况相等并且这个根两种情况相等就是no； 最终的根节点的两种情况相等也是no。 其他的就是yes了。 Followed by: Post your reply here: |
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