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Re:请教这道题还有哪些地方可以剪枝啊,我找了三个地方,不过还要46ms,看到很多人0秒过的.........In Reply To:请教这道题还有哪些地方可以剪枝啊,我找了三个地方,不过还要46ms,看到很多人0秒过的......... Posted by:KosonLau at 2007-05-19 13:56:20 > 下面注释的三个地方为剪枝...... > > (附代码,仅供交流...) > #include<iostream> > using namespace std; > #include<stdio.h> > #define MAX 100000 > const int maxr=25; > const int maxh=25; > int n,m; > int mins; > int minv[26],maxv[26][26]; > void set() > { > int i,j; > minv[0]=0; > for(i=1;i<=maxr;i++) > { > minv[i]=minv[i-1]+i*i*i; > } > for(i=0;i<=maxr;i++) > { > maxv[i][0]=0; > maxv[0][i]=0; > } > for(i=1;i<=maxr;i++) > for(j=1;j<=maxr;j++) > { > maxv[i][j]=maxv[i-1][j-1]+i*i*j; > } > } > void search(int floor,int r,int h,int v,int s) > { > v-=r*r*h; > s+=2*r*h; > if(floor==m) > { > > if(v==0) > { > if(s<mins) > mins=s; > } > return; > } > if(v<=0||s>mins) //剪枝,当前所得到的总面积大于已求得最小总面积,或剩余体积小于0 > return; > int i,j; > floor++; > int left=m-floor+1; > > if((maxv[r-1][h-1]-maxv[r-left-1][h-left-1])<v) //剪枝,剩余体积大于当层以上的所有层的最大体积和 > return; > > if(minv[left]>v) //剪枝,剩余体积小于当层以上的所有层的最小体积和 > return; > > for(i=r-1;i>=left;i--) > for(j=h-1;j>=left;j--) > { > search(floor,i,j,v,s); > } > } > int main() > { > int i,j; > set(); > while(scanf("%d%d",&n,&m)==2) > { > mins=MAX; > for(i=maxr;i>=m;i--) > for(j=maxh;j>=m;j--) > { > search(1,i,j,n,i*i); > } > if(mins==MAX) > printf("0\n",mins); > else > printf("%d\n",mins); > } > return 0; > } Followed by: Post your reply here: |
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