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我算的还是21227,我这里是vc或者g++编译器In Reply To:Re:绝对没问题 Posted by:kknd123 at 2005-03-02 21:04:05 结果都是这个 > #include <stdio.h> > #include <math.h> > void main(){ > int p,e,i,d,j,no=1; > scanf("%d %d %d %d\n",&p,&e,&i,&d); > while(p!=-1 && e!=-1 && i!=-1 && d!=-1){ > for(j=d+1; j<=21252; j++) if ((j-p)%23 == 0) break; > for( ; j<=21252; j=j+23) if ((j-e)%28 == 0) break; > for( ; j<=21252; j=j+23*28) if ((j-i)%33 == 0) break; > printf("Case %d: the next triple peak occurs in %d days.\n",no,j-d); > scanf("%d %d %d %d\n",&p,&e,&i,&d); > no++; > } > } > > 这个是原程序。根据上述数据i=21254 Followed by:
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