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我算的还是21227,我这里是vc或者g++编译器

Posted by hawk at 2005-03-02 21:10:57 on Problem 1006
In Reply To:Re:绝对没问题 Posted by:kknd123 at 2005-03-02 21:04:05
结果都是这个

> #include <stdio.h>
> #include <math.h>
> void main(){
>           int p,e,i,d,j,no=1;
>           scanf("%d %d %d %d\n",&p,&e,&i,&d);
>           while(p!=-1 && e!=-1 && i!=-1 && d!=-1){
>                 for(j=d+1; j<=21252; j++)     if ((j-p)%23 == 0) break;
>                 for( ; j<=21252; j=j+23)         if ((j-e)%28 == 0) break;
>                 for( ; j<=21252; j=j+23*28)  if ((j-i)%33 == 0) break;
>                 printf("Case %d: the next triple peak occurs in %d days.\n",no,j-d);       
>                 scanf("%d %d %d %d\n",&p,&e,&i,&d);
>                 no++;
>          }
> }
> 
> 这个是原程序。根据上述数据i=21254

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