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标准答案#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char map[] = "22233344455566677778889999";
char str[80], telNumbers[100000][9];
int compare(const void *elem1,const void *elem2) {
//为函数模板 sort 定义数组元素的比较函数
return (strcmp((char*)elem1, (char*)elem2));
};
void standardizeTel(int n) {
int j, k;
j = k = -1 ;
while ( k<8 ) {
j++;
if ( str[j] == '-' )
continue;
k++;
if (k==3) {
telNumbers[n][k]='-';
k++;
}
if(str[j]>='A' && str[j]<='Z') {
telNumbers[n][k]=map[str[j]-'A'];
continue;
};
telNumbers[n][k]=str[j];
}
telNumbers[n][k]='\0';
return;
}
void main()
{
int n,i,j;
bool noduplicate;
scanf("%d",&n);
for(i=0;i<n;i++){//输入电话号码,存储到数组 telNumbers 中
scanf("%s",str);
standardizeTel(i);
//将 str中的电话号码转换成标准形式,存储在 telNu
}
qsort(telNumbers,n,9,compare);//对输入的电话号码进行排序
noduplicate = true;
i=0;
while(i<n){//搜索重复的电话号码,并进行输出
j=i;
i++;
while(i<n&&strcmp(telNumbers[i], telNumbers[j])==0) i++;
if(i-j>1) {
printf("%s %d\n", telNumbers[j], i-j);
noduplicate = false;
}
}
if ( noduplicate )
printf("No duplicates.\n");
}
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