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妙啊！In Reply To:思路~ Posted by:5l2 at 2008-07-20 11:12:37 设a>b之后 |x0+b/d *t| 单调递增，|y0-a/d*t| 先递减再递增。因斜率a/d>b/d，所以总的|x0+b/d *t |+|y0-a/d *t| 先递减再递增，使y0-a/d*t0=0 的t0附近有最小值。 Followed by:
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