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Re:哪位大牛给个可以让我检查出错的数据In Reply To:Re:哪位大牛给个可以让我检查出错的数据 Posted by:hebeboy at 2008-08-15 09:53:25 > #include "stdio.h" > #include "string.h" > > void main() > {char a[110]="0",b[110]="0"; > int c[27],d[27],i,j,m,n,l,s,k,temp=0,tem=0,x=1,y,h,g; > for(y=0;y<=25;y++) > {c[y]=0; > d[y]=0; > } > scanf("%s",a); > scanf("%s",b); > for(i=0;i<=99;i++) > { if(a[i]=='A')c[0]++; > else if(a[i]=='B')c[1]++; > else if(a[i]=='C')c[2]++; > else if(a[i]=='D')c[3]++; > else if(a[i]=='E')c[4]++; > else if(a[i]=='F')c[5]++; > else if(a[i]=='G')c[6]++; > else if(a[i]=='H')c[7]++; > else if(a[i]=='I')c[8]++; > else if(a[i]=='J')c[9]++; > else if(a[i]=='K')c[10]++; > else if(a[i]=='L')c[11]++; > else if(a[i]=='M')c[12]++; > else if(a[i]=='N')c[13]++; > else if(a[i]=='O')c[14]++; > else if(a[i]=='P')c[15]++; > else if(a[i]=='Q')c[16]++; > else if(a[i]=='R')c[17]++; > else if(a[i]=='S')c[18]++; > else if(a[i]=='T')c[19]++; > else if(a[i]=='U')c[20]++; > else if(a[i]=='V')c[21]++; > else if(a[i]=='W')c[22]++; > else if(a[i]=='X')c[23]++; > else if(a[i]=='Y')c[24]++; > else if(a[i]=='Z')c[25]++; > } > for(j=0;j<=99;j++) > { if(b[j]=='A')d[0]++; > else if(b[j]=='B')d[1]++; > else if(b[j]=='C')d[2]++; > else if(b[j]=='D')d[3]++; > else if(b[j]=='E')d[4]++; > else if(b[j]=='F')d[5]++; > else if(b[j]=='G')d[6]++; > else if(b[j]=='H')d[7]++; > else if(b[j]=='I')d[8]++; > else if(b[j]=='J')d[9]++; > else if(b[j]=='K')d[10]++; > else if(b[j]=='L')d[11]++; > else if(b[j]=='M')d[12]++; > else if(b[j]=='N')d[13]++; > else if(b[j]=='O')d[14]++; > else if(b[j]=='P')d[15]++; > else if(b[j]=='Q')d[16]++; > else if(b[j]=='R')d[17]++; > else if(b[j]=='S')d[18]++; > else if(b[j]=='T')d[19]++; > else if(b[j]=='U')d[20]++; > else if(b[j]=='V')d[21]++; > else if(b[j]=='W')d[22]++; > else if(b[j]=='X')d[23]++; > else if(b[j]=='Y')d[24]++; > else if(b[j]=='Z')d[25]++; > } > > > > for(l=1;l<=25;l++) > for(m=l;m<=26-l;m++) > { if(c[m]<=c[m-1]) > {temp=c[m]; > c[m]=c[m-1]; > c[m-1]=temp; > } > } > > for(s=1;s<=25;s++) > for(k=1;k<=26-s;k++) > { if(d[k]<=d[k-1]) > {tem=d[k]; > d[k]=d[k-1]; > d[k-1]=tem; > } > } > > for(n=0;n<=25;n++) > {if(c[n]!=d[n])x=0; > } > if(x==0)printf("NO"); > else if(x==1)printf("YES"); > > > } > Followed by:
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