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A*,32MS,90道题目留念

Posted by Jonathan at 2009-06-12 00:09:12 on Problem 1077
评估函数
f2(x)= p(x)+3s(x)
p(x)是x结点和目标结点相比每个将牌“离家”的最短距离之和;
s(x)是:每个将牌和目标相比,若该将牌的后继和目标中该将牌的后继不同,
则该将牌得2分,相同则该将牌得0分,中间位置有将牌得1分,没将牌得0分。

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