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开始觉得要打表,最后发现有公式,水一个~~~#include<iostream>
using namespace std;
int main()
{
int t,x,y;
cin>>t;
while(t--)
{
cin>>x>>y;
if (x==y)
{
if(x%2)cout<<2*x-1<<endl;
else cout<<2*x<<endl;
}
else if (x-2==y)
{
if(x%2)cout<<2*x-3<<endl;
else cout<<2*x-2<<endl;
}
else
{
cout<<"No Number\n";
}
}
return 0;
}
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