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来个超时的代码吧#include <iostream>
using namespace std;
int main()
{
unsigned long a;
while(cin>>a)
{
unsigned long b,c,sum=10000000000000000000;
for(b=a+1;b<=a*a+a+1;b++)
{
if((a*b+1)%(b-a)==0)
{
c=(a*b+1)/(b-a);
if(sum>(b+c)) sum=b+c;
}
}
cout<<sum<<endl;
}
return 0;
}
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