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这个也runtime ?#include<iostream>
using namespace std;
int main()
{
int a[10000];
int i,j,k,n;
//freopen("a.in","r",stdin);
//freopen("a.out","w",stdout);
j=1;k=1;a[0]=0;
for (i=1;i<=10000;i++)
{
a[i]=a[i-1]+k;
if (j==i)
{
k++;
j+=k;
}
}
while (cin>>n && n!=0)
cout<<n<<" "<<a[n]<<endl;
return 0;
}
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