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超水！！ 0MS就ok 代码共享#include <iostream>
using namespace std;
int main()
{
int N;
double x;
int count=1,sum;
int tempory;
double a1;
cin>>N;
while(count<=N)
{ cin>>tempory>>x;
sum=0;
for(int n=2;n<=70000;n++)
{
a1=(2.0*x/n-n+1)/2;
if(a1>0&&a1==long(a1)) sum++;
if(a1<=0) break;
}
cout<<count<<" "<<sum<<endl;
count++;
}
return 0;
}
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