> 谢谢
附上程序：
#include "stdio.h"
int main()
{int p[20]={0},e[20],i[20],d[20],j,k=0;
 long p1,e1,i1,num[20];
 do{ 
    scanf("%d%d%d%d",&p[k],&e[k],&i[k],&d[k]);
   }while(p[k++]>-1);
 for(j=0;j<k-1;j++)   
    {p1=(p[j]%23)*5544;
     e1=(e[j]%28)*14421;
     i1=(i[j]%33)*1288;
     p1+=e1+i1;
     num[j]=p1-(p1/21252)*21252-d[j];
    }
  for(j=1;j<k;j++)
     {if(num[j-1]<=0) num[j-1]+=21252;
      printf("Case %d: the next triple peak occurs in %ld days.\n",j,num[j-1]);
     }
 return 0;
}