> #include<iostream>
> #include<cstring>
> #include<cmath>
> using namespace std;
> 
> int dif[3000];
> 
> int main(){
> 	int n;
> 	while(cin >> n){
> 		memset(dif,0,sizeof(dif));
> 		int pre,current;
> 		cin >> pre;
> 		int i;
> 		for(i = 1; i < n; i++){
> 			cin >> current;
> 			int abs_dif = abs(current - pre);
> 			dif[abs_dif] = 1;
> 			pre = current; 	
> 		}
> 		
> 		for(i = 1; i < n; i++){
> 			if(dif[i] == 0)
> 				break;
> 		}
> 
> 		if(i == n)
> 			cout << "Jolly" << endl;
> 		else
> 			cout << "Not jolly" << endl;
> 	}
> }

• Re:一个简单的代码 (74) peterdi 2009-05-17 21:37:51
• Re:一个简单的代码 (9) 345952100 2009-09-08 08:37:58
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