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其实还有个投机的方法In Reply To:无意间发现简单的算法! Posted by:lovexx at 2006-07-25 23:53:44 就是现将原来那个数所有位上的数的和算出来保存为Sum，然后就乘吧，每次得出的一个数算算它所有位上数的和，如果和Sum不相等就显然不是循环数，倘若所有的乘积都满足这个条件，我们就“认为”它是循环数，因为不是循环数而每次的乘积都满足这个条件太困难了，尤其是位数比较长的时候。嘿嘿，用这种投机的方法Accept了 Followed by: Post your reply here: |
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