#include <iostream.h>
#include <math.h>
#include <string.h>
	char *str[]={"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol"
		, "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab"
		, "cumhu","uayet"};
	char *tzolkin[]={"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk"
		, "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", 
		"eznab", "canac", "ahau"};




void main(){
	int number;
	int count=0;
	cin>>number;
	cin.get();
	while(count<number){

	char input[20];
	char month[6];

	cin.getline(input,20);
	
	int k=0;
	long day=0;
	long year=0;
	long total=0;
	
		while(input[k]!='.')
		{
			k++;
		
		}
		for(int j=0;j<k;j++)
		{
			day+=(input[j]-'0')*long(pow(10,k-j-1));}
	
	
		for(int i=0;input[i]!='\0';i++);
	
	for( j=i-1;input[j]!=' ';j--)
	{
		year+=(input[j]-'0')*long(pow(10,i-j-1));}
	j=0;
	for(i=k+2;input[i]<='z'&&input[i]>='a';i++)
	{
		month[j]=input[i];
		j++;}
	month[j]='\0';


	for(i=0;i<20;i++)
	{
		 for(j=0;month[j]!='\0';j++)
		 {
			 if(month[j]!=str[i][j])
				 break;}
		 if(month[j]=='\0')
			 break;
	}
			 
	
	 total=year*365+i*20+day;
	year=total/260;
	day=total%13+1;
	
	long monthnum=(total%20);
		

		cout<<day<<" "<<tzolkin[monthnum]<<" "<<year<<endl;
	
		count++;}
	
	
}

• 改为year=(total-1)/260怎样，否则每年的最后一天计算年数不正确 (0) 00448072 2005-03-04 16:59:07
  • 太感谢了，就是这样 (2) 00448087 2005-03-13 20:22:58
    • Re:太感谢了，就是这样 (17) hubo1016 2005-05-02 14:17:23