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一个细节if you can remove characters from t such that the concatenation of the remaining characters is 表示删除后面的一些元素后可以找到前面的字符串则还是Yes #include<iostream> #include<string> #include<fstream> using namespace std; int main(int argc, char* argv[]) { string a,b; //fstream cin("aaa.txt"); while(cin>>a>>b) { int le=a.length(); int count=0,i=0,j=0; if(a.length()>b.length()){printf("No\n");continue;} for(i=0;j!=b.length()&&i<a.length();) { if(a[i]==b[j]){i++;j++;count++;} else {j++;} } if(count==a.length())printf("Yes\n"); else printf("No\n"); } return 0; } Followed by: Post your reply here: |
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