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用经典的贪心就可以了In Reply To:刚才的程序沾错了 Posted by:liuminghai at 2005-02-23 15:11:42 > #include <iostream.h>
> #include <memory.h>
>
> int n, t, x[20], map[20][20];
> void main()
> {
> int i, j, k, max, min, t1, t2, boolean;
> cin>>t;
> for (i = 0; i < t; i++) {
> memset(x, 0, sizeof(x));
> memset(map, 0, sizeof(map));
> boolean = 0;
> cin>>n;
> for (j = 0; j < n; j++) {
> cin>>x[j];
> if (x[j]) boolean = 1;
> }
> while (boolean) {
> min = 100; max = 0;
> for (j = 0; j < n; j++)
> if (x[j] < min && x[j]) {
> min = x[j]; t1 = j;
> }
> for (j = n - 1; j >= 0; j--)
> if (x[j] > max) {
> max = x[j]; t2 = j;
> }
> if (min == 100) break;
> if (t1 == t2) {
> boolean = 0; break;
> }
> if (t1 == t2)
> for (j = t1 + 1; j < n; j++)
> if (max == x[j]) {
> t2 = j; break;
> }
> if (map[t1][t2] == 1) {
> boolean = 0; break;
> }
> x[t1]--; x[t2]--;
> map[t1][t2] = 1; map[t2][t1] =1;
> }
> if (boolean == 0) {
> cout<<"NO"<<endl;
> if (i < t - 1) cout<<endl;
> }
> else {
> cout<<"YES"<<endl;
> for (j = 0; j < n; j++) {
> for (k = 0; k < n - 1; k++)
> cout<<map[j][k]<<' ';
> cout<<map[j][k]<<endl;
> }
> if (i < t - 1) cout<<endl;
> }
> }
> }
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