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用经典的贪心就可以了In Reply To:刚才的程序沾错了 Posted by:liuminghai at 2005-02-23 15:11:42 > #include <iostream.h> > #include <memory.h> > > int n, t, x[20], map[20][20]; > void main() > { > int i, j, k, max, min, t1, t2, boolean; > cin>>t; > for (i = 0; i < t; i++) { > memset(x, 0, sizeof(x)); > memset(map, 0, sizeof(map)); > boolean = 0; > cin>>n; > for (j = 0; j < n; j++) { > cin>>x[j]; > if (x[j]) boolean = 1; > } > while (boolean) { > min = 100; max = 0; > for (j = 0; j < n; j++) > if (x[j] < min && x[j]) { > min = x[j]; t1 = j; > } > for (j = n - 1; j >= 0; j--) > if (x[j] > max) { > max = x[j]; t2 = j; > } > if (min == 100) break; > if (t1 == t2) { > boolean = 0; break; > } > if (t1 == t2) > for (j = t1 + 1; j < n; j++) > if (max == x[j]) { > t2 = j; break; > } > if (map[t1][t2] == 1) { > boolean = 0; break; > } > x[t1]--; x[t2]--; > map[t1][t2] = 1; map[t2][t1] =1; > } > if (boolean == 0) { > cout<<"NO"<<endl; > if (i < t - 1) cout<<endl; > } > else { > cout<<"YES"<<endl; > for (j = 0; j < n; j++) { > for (k = 0; k < n - 1; k++) > cout<<map[j][k]<<' '; > cout<<map[j][k]<<endl; > } > if (i < t - 1) cout<<endl; > } > } > } Followed by:
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