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Re:害人不浅,题目倒是挺简单,就是说的不明白。害得我忙了一下午。标点可以重复计数,但是ff等只计一次。给出参考In Reply To:害人不浅,题目倒是挺简单,就是说的不明白。害得我忙了一下午。标点可以重复计数,但是ff等只计一次。给出参考 Posted by:20083331 at 2009-05-04 16:54:54 > #include<iostream> > #include<cstring> > using namespace std; > > int map[256]={0}; > int main() > { > int i; > //这里有点罗嗦了 > for(i='a';i<='z';i++) > map[i]=0; > for(i='A';i<='Z';i++) > map[i]=0; > > map[5]=0;//it is ff > map[6]=0;//it is fi > map[7]=0;//it is fl > map[8]=0;//it is ffi > map[9]=0;//it is ffl > > > char record[105]; > int count=0; > > while(cin>>record) > { > int len=strlen(record); > for(i=0;i<len;i++) > { > // it is `` > if(record[i]=='`' && record[i+1]=='`') > { > count++; > i++; > continue; > } > if(record[i]=='`') > { > count++; > continue; > } > // it is '' > if(record[i]=='\'' && record[i+1]=='\'') > { > count++; > i++; > continue; > } > if(record[i]=='\'') > { > count++; > continue; > } > // it is ffi > // it is ffl > if(record[i]=='f' && record[i+1]=='f' && (record[i+2]=='i' || record[i+2]=='l')) > { > > if(record[i+2]=='i') > { > if(map[8]==0) > count++; > map[8]=1; > } > else > { > if(map[9]==0) > count++; > map[9]=1; > } > i=i+2; > continue; > } > // it is ff fi fl > if(record[i]=='f' && (record[i+1]=='f' || record[i+1]=='i' || record[i+1]=='l')) > { > if(record[i+1]=='f') > { > if(map[5]==0) > count++; > map[5]=1; > } > else if(record[i+1]=='i') > { > if(map[6]==0) > count++; > map[6]=1; > } > else > { > if(map[7]==0) > count++; > map[7]=1; > } > i++; > continue; > } > > > if(map[(int)record[i]]!=1) > { > //cout<<"we have count this number"<<endl; > count++; > map[(int)record[i]]=1; > } > } > // cout<<"this period is"<<count<<endl; > } > cout<<count<<endl; > > return 0; > } Followed by: Post your reply here: |
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