#include<iostream>
#include<cstring>
#include<cmath>
using namespace std;

int dif[3000];

int main(){
	int n;
	while(cin >> n){
		memset(dif,0,sizeof(dif));
		int pre,current;
		cin >> pre;
		int i;
		for(i = 1; i < n; i++){
			cin >> current;
			int abs_dif = abs(current - pre);
			dif[abs_dif] = 1;
			pre = current; 	
		}
		
		for(i = 1; i < n; i++){
			if(dif[i] == 0)
				break;
		}

		if(i == n)
			cout << "Jolly" << endl;
		else
			cout << "Not jolly" << endl;
	}
}

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• Re:一个简单的代码 (572) yuech 2009-07-15 10:19:57
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• Re:一个简单的代码 (592) xuanwo 2014-02-10 15:58:08