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Re:不要想复杂，按照字符串输入之后，就for (i=0;s[i];i++) {n+=s[i]-'0'; if (n>9) n-=9;}就这就搞定了哈。In Reply To:不要想复杂，按照字符串输入之后，就for (i=0;s[i];i++) {n+=s[i]-'0'; if (n>9) n-=9;}就这就搞定了哈。 Posted by:bluegenelove at 2007-09-29 23:53:27 多谢，原来我还要来回转换，而你这样就可以避免很多麻烦了。 Followed by: Post your reply here: |
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