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注意N=0的情况 if(n) printf("Number of doors = %ld\n",ans+1) ; else printf("Number of doors = 1\n") ;我开始注意到了但是else语句只输出了1，忘记了打字符串。。枚举边上的所有点形成线段的中点，与给定的点连线段，这条线段与所有题目中输入的线段的交点数之和+1就是答案。 另 边上一共有k+1的点要去判断。。 Followed by:
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